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2x^2-3x=-4x-1
We move all terms to the left:
2x^2-3x-(-4x-1)=0
We get rid of parentheses
2x^2-3x+4x+1=0
We add all the numbers together, and all the variables
2x^2+x+1=0
a = 2; b = 1; c = +1;
Δ = b2-4ac
Δ = 12-4·2·1
Δ = -7
Delta is less than zero, so there is no solution for the equation
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